1次関数の式を
　答えよう
傾き[1/2]　切片+3
 y=[1/2]x+3
傾き2 切片-5
　y=2x-5
傾き-3　切片+2
　y=-3x+2
傾き[2/5] 切片+4
　y=[2/5]x+4
傾き-[3/5] 切片-5
　y=-[3/5]x-5
傾き-[4/3] 切片+1
　y=-[4/3]x+1
傾き-5 切片-[2/3]
　y=-5x-[2/3]
傾き[1/2] 切片-[3/2] 
　y=[1/2]x-[3/2]
傾き[2/3] 切片[1/3]
　y=-[2/3]x+[1/3]